( + ) each classes , answer = / total all classes
arrange the numbers in order from smallest to largest, find the midpoint
number frequency
create table, age-frequency-classmart-frequencyclassmart.
1. Frequency Collumn calculate all total data
2. Class Mart Collumn "age" plus ( 10 - 15 ) > ( 10 + 15 = 25 )
3.Frequency CM Collumn "f" x "each answer sm"
create table, age(month)-numbercomputer-boundarycomulative-frequency-class width
1. Number Computer calculate all data
2. Boundary Comulative every data must add 0.5 ( 10 ) - 10.5 , if data was 10 to 20 the boundry will be ( 10.5 -20.5 )
3. Comulative Frequency , first row ( 10 ) plus with second row ( 35 ) get asnwer for comulative frequency for row two = ( 45 )
4. Class Width , you can analys from the age collumn, "age" 21 - 25, to get class width you need to minus ( - ) , for examples (21 - 25) = 5. the answer is 5#
next step
formula £f+1 -> £100+1\2
LB = 50.5
L = 5
F = 45
f = 16
LB+C [£f+1\2-F]
= 30.5+6 [50.5 - 45]/16
= 32.22