only cooh
coo-na+. +h20
(coo-)2mg +h2
h+
it can attract cl2 more easily
sidewwys overlap of p orbitals
hesd on overlwp of p orbitals
both involve the overlappimf of p orbitwls
1) kekule consiste of slternwtimg pi bomds whereas the deloclaised model has the pi bonds delocalised wcross the whole ring
1) it does not discoloursie bromine water
2) the dehyrogenwtioj of cyclohexene is -120kjmol so we would expect the dehdrogenetwtiom of benzene ro be -360 but ir is actyally less exothermic thsn oredicted
a known database
H+ /KCN
si(ch3)4
major product formed from more stable cwrbocwtion
nh3+
work it out then add the remaining mr for what is not included in the polyester
no
only carobylic acid
both phenol and csrbocylic acid
- further wubsitution mwy occur
- subisituion ,ay occur on any cwrbin atom in the cwrbon chwin
to idemtify oh or nh protons
either nh2 or nh3 plus
bresking of covalent bond in which each atom recovd 1 electron from the bonding pair
pi has a weaker
1
cwrboxylic acids amd phemols
not alchols
only carboylic acids
overlap of obitals between bonding atoms
sideways overlap of adjecent orbiatls
super non imposbsle mirror images around a chiral carbon
H+/H20
1
yes
h plus and h20
so2 and hcl
both the carboxyl acid snd product have a 2
alchol
the h in hbr accepets a pair of electrons
obtain mp usimg mp apprartus compare ranges to known value if pure narorr mp range if impure range widens
HCL (aq) and H20(l)
phenol with 3 BR
1) mark a baslime that is insoluble im mobile phase
2) mobile phase must be in a liquid solvent which wmino acid dissolves in
3) solvent must be below baseline
4) stationwry phase is the adsorbwnr substsnce on TLC plwte
5) dot sample on baseline
6) lesve ro run inna tank with lid on
7) remove plare approx 1cm before solvent resches top
8) mark solvent dromt wmd lesve to dry
9) use UV ligjt to make spots visable
unrewctive
si (ch3)4
inert wnd unrewctige so will not interfee with substance
replaces the h onnthe oh or nh so pesk not shown in secojd trace
percentage yield x moles
moles/ percentwge yield
kekule has alternating pi bonds whereas delocalised has a pi rung which all p orbitals overlap
resct rewdily by addition
ch3 on one side amd h on the other
excess nh3 and ethanol
in equation write 2nh3
1) dissolve in a minium volume of hot solvent
2) cool solution and filter solid
3) wash with cold water and dry
1) ohtain mp
2) compare to known vakues
3) if pure it will have a sharp mp close to the data book value
4) if impure will have a wider mp range
1) add to a seperating funnel
2) organic layer settles om top ( if density is less than water )
3) dry with an anhydrous salt
4) redistill
1) a pencil line is drawn horizontally about 1 cm from the base of the plate
2) a spot of sample is added to the line and allowed to dry
3) the plste is then added to a beaker containing a solvent at the bottom
4) ths solvent is allowed to rise up the plate
the time taken for component to travel through the collum
which is then compwred to a known database of known values
10^-6
x1000
then divide by mr
to get moldm3
h